benjamin dickman
@benjamindickman.bsky.social
K-12 math educator 🪄♾️
Brookline to Nanjing to NYC
Amherst College BA
Fulbright Program x2 (🇨🇳+🇵🇭)
Teachers College, Columbia University PhD
past BU Wheelock (postdoc, Math Edu)
cocreated original word game: #FiddleBrix
http://tinyurl.com/bmdmaths
Brookline to Nanjing to NYC
Amherst College BA
Fulbright Program x2 (🇨🇳+🇵🇭)
Teachers College, Columbia University PhD
past BU Wheelock (postdoc, Math Edu)
cocreated original word game: #FiddleBrix
http://tinyurl.com/bmdmaths
that's my dream for Expo markers
November 28, 2025 at 2:42 PM
that's my dream for Expo markers
still yet more math edu posting & hand-wringing (no post from me is an endorsement unless explicitly stated as such!):
www.insidehighered.com/opinion/colu...
www.insidehighered.com/opinion/colu...
The New Cliff Facing Higher Ed & How AI Might Help Solve It
There is a new “cliff” in American higher education, and it is not the demographic cliff. Rather, it is the dramatic cliff in math knowledge, skills and abilities.
www.insidehighered.com
November 27, 2025 at 12:49 AM
still yet more math edu posting & hand-wringing (no post from me is an endorsement unless explicitly stated as such!):
www.insidehighered.com/opinion/colu...
www.insidehighered.com/opinion/colu...
ok finessed a second Wed #2solve just to have something diff:
01010000 01001111 01001100 01011001 01001101 01001111 01010010 01010000 01001000 01001001 01000011 00100000 01000011 01010010 01001111 01010111 01000100 01010011
01010000 01001111 01001100 01011001 01001101 01001111 01010010 01010000 01001000 01001001 01000011 00100000 01000011 01010010 01001111 01010111 01000100 01010011
November 26, 2025 at 2:49 PM
ok finessed a second Wed #2solve just to have something diff:
01010000 01001111 01001100 01011001 01001101 01001111 01010010 01010000 01001000 01001001 01000011 00100000 01000011 01010010 01001111 01010111 01000100 01010011
01010000 01001111 01001100 01011001 01001101 01001111 01010010 01010000 01001000 01001001 01000011 00100000 01000011 01010010 01001111 01010111 01000100 01010011
oh read the English translation (unless your French is better than I knew)
November 26, 2025 at 1:39 AM
oh read the English translation (unless your French is better than I knew)
yeah: "A Lover's Discourse: Fragments"
just googling it will yield the full PDF
just googling it will yield the full PDF
November 26, 2025 at 1:27 AM
yeah: "A Lover's Discourse: Fragments"
just googling it will yield the full PDF
just googling it will yield the full PDF
s/o this post for inspo
bsky.app/profile/moti...
bsky.app/profile/moti...
Proposing an off-campus study program in which I take students to the Platonic Realm and we observe the Forms in their natural habitat.
November 26, 2025 at 12:09 AM
s/o this post for inspo
bsky.app/profile/moti...
bsky.app/profile/moti...
ok it's niche but is it too niche
November 25, 2025 at 11:44 PM
ok it's niche but is it too niche
follow up:
how many switches are required to get from 54321 to 12345?
what about the general case?
(can you prove it?!)
#MathSky 🧮 #MathsToday 🔢
how many switches are required to get from 54321 to 12345?
what about the general case?
(can you prove it?!)
#MathSky 🧮 #MathsToday 🔢
November 25, 2025 at 2:30 PM
follow up:
how many switches are required to get from 54321 to 12345?
what about the general case?
(can you prove it?!)
#MathSky 🧮 #MathsToday 🔢
how many switches are required to get from 54321 to 12345?
what about the general case?
(can you prove it?!)
#MathSky 🧮 #MathsToday 🔢
more mainstream math edu coverage (different flavor than the above):
www.edweek.org/teaching-lea...
www.edweek.org/teaching-lea...
How to Make Every Student Feel Like a ‘Math Person’ (Opinion)
Math teachers and researchers discuss how to make the subject more engaging and accessible.
www.edweek.org
November 25, 2025 at 1:00 PM
more mainstream math edu coverage (different flavor than the above):
www.edweek.org/teaching-lea...
www.edweek.org/teaching-lea...
Tue solve #2solve: Gizmo Griffin
01010001 01010101 01000001 01001000 01001111 01000111 00100000 01000111 01010010 01000101 01001101 01001100 01001001 01001110
01010001 01010101 01000001 01001000 01001111 01000111 00100000 01000111 01010010 01000101 01001101 01001100 01001001 01001110
November 25, 2025 at 12:28 PM
Tue solve #2solve: Gizmo Griffin
01010001 01010101 01000001 01001000 01001111 01000111 00100000 01000111 01010010 01000101 01001101 01001100 01001001 01001110
01010001 01010101 01000001 01001000 01001111 01000111 00100000 01000111 01010010 01000101 01001101 01001100 01001001 01001110
i understood that as, couldn't tell you what e.g. 3/5 ÷ 2 is
November 24, 2025 at 10:11 PM
i understood that as, couldn't tell you what e.g. 3/5 ÷ 2 is
... gotta love an increasing sequence that, in the current times and climate, goes from 5 directly to 8
the children are DEVASTATED!
the children are DEVASTATED!
November 23, 2025 at 7:20 PM
... gotta love an increasing sequence that, in the current times and climate, goes from 5 directly to 8
the children are DEVASTATED!
the children are DEVASTATED!
FIND HIM !
IT IS THE WAY FORWARD !
phd with a giant of math education (jeremy kilpatrick) after working as a TA for george polya
IT IS THE WAY FORWARD !
phd with a giant of math education (jeremy kilpatrick) after working as a TA for george polya
November 23, 2025 at 5:49 PM
FIND HIM !
IT IS THE WAY FORWARD !
phd with a giant of math education (jeremy kilpatrick) after working as a TA for george polya
IT IS THE WAY FORWARD !
phd with a giant of math education (jeremy kilpatrick) after working as a TA for george polya
... you're at SCSU?? i hope you've run into Phil Smith ("J. Philip Smith") by now ... that is my teaching mentor from grad school. outstanding instructor
November 23, 2025 at 5:38 PM
... you're at SCSU?? i hope you've run into Phil Smith ("J. Philip Smith") by now ... that is my teaching mentor from grad school. outstanding instructor
so this gives you the recursive formula, right?
because you can take:
x^3 = 2x^2 - x + 1
and shift the exponents by n-3 to get:
x^n = 2x^(n-1) - x^(n-2) + x^(n-3)
which is what comes out of
f(n) = 2f(n-1) - f(n-2) + f(n-3)
(couldn't tell if this was already in your spreadsheet part & i missed it)
because you can take:
x^3 = 2x^2 - x + 1
and shift the exponents by n-3 to get:
x^n = 2x^(n-1) - x^(n-2) + x^(n-3)
which is what comes out of
f(n) = 2f(n-1) - f(n-2) + f(n-3)
(couldn't tell if this was already in your spreadsheet part & i missed it)
November 23, 2025 at 5:00 PM
so this gives you the recursive formula, right?
because you can take:
x^3 = 2x^2 - x + 1
and shift the exponents by n-3 to get:
x^n = 2x^(n-1) - x^(n-2) + x^(n-3)
which is what comes out of
f(n) = 2f(n-1) - f(n-2) + f(n-3)
(couldn't tell if this was already in your spreadsheet part & i missed it)
because you can take:
x^3 = 2x^2 - x + 1
and shift the exponents by n-3 to get:
x^n = 2x^(n-1) - x^(n-2) + x^(n-3)
which is what comes out of
f(n) = 2f(n-1) - f(n-2) + f(n-3)
(couldn't tell if this was already in your spreadsheet part & i missed it)
this is awesome!!
i was expecting a solution that's like, use a 0 to indicate "exclude" and a 1 to indicate "include" so that this problem equivalently asks:
"how many binary strings of length n avoid the substring 101?"
diagonalizing a matrix not on my bingo card (or in my tool kit). great stuff
i was expecting a solution that's like, use a 0 to indicate "exclude" and a 1 to indicate "include" so that this problem equivalently asks:
"how many binary strings of length n avoid the substring 101?"
diagonalizing a matrix not on my bingo card (or in my tool kit). great stuff
November 23, 2025 at 4:58 PM
this is awesome!!
i was expecting a solution that's like, use a 0 to indicate "exclude" and a 1 to indicate "include" so that this problem equivalently asks:
"how many binary strings of length n avoid the substring 101?"
diagonalizing a matrix not on my bingo card (or in my tool kit). great stuff
i was expecting a solution that's like, use a 0 to indicate "exclude" and a 1 to indicate "include" so that this problem equivalently asks:
"how many binary strings of length n avoid the substring 101?"
diagonalizing a matrix not on my bingo card (or in my tool kit). great stuff