stewmc.bsky.social
@stewmc.bsky.social
astatine
July 27, 2025 at 9:11 PM
I went for:
Rotate the hyperbola into standard position, 20xx - 45yy - 100 = 0.
Set y=0. Find x ie radius of circle = root5
July 18, 2025 at 12:43 PM
📌
July 8, 2025 at 6:35 PM
Eeeeeeat poppadoms,
Eeeeeeat poppadoms, yeyeah
June 9, 2025 at 3:35 PM
"Theorem 15... Proof. Since cos is an odd function.."
Is cos not an even function? Or is that part of the eventual contradiction?
June 1, 2025 at 6:27 PM
*biro packing
May 5, 2025 at 4:02 PM
I'm sure I counted those. Wait, maybe, yeah definitely did, or, possibly not, hang on...
March 23, 2025 at 8:51 PM
Multiply by 5 because you can do the same at each outer pentagon vertex. And divide by 1, 2 or 3 because that's how many times you'd count the same triangle.
March 23, 2025 at 8:49 PM
Initially, I just went for it and hoped not to double count anything.

Then, noting that each triangle has at least one vertex on the outer pentagon, choose a vertex, count triangles with 1 pentagon vertex, repeat for two vertices, then three. I get 1, 8 and 6.

1x5/1 + 8x5/2 + 6x5/3 = 35

I think.
March 23, 2025 at 8:47 PM
35
March 23, 2025 at 10:43 AM
📌
January 30, 2025 at 8:23 PM
Reposted
I haven't seen GraspableMath before, it looks pretty good. Thanks for that one. mathswhiteboard.com is good for throwing up questions for students to try.
MWB
mathswhiteboard.com
December 15, 2024 at 12:06 PM
I haven't seen GraspableMath before, it looks pretty good. Thanks for that one. mathswhiteboard.com is good for throwing up questions for students to try.
MWB
mathswhiteboard.com
December 15, 2024 at 12:06 PM
That's quite a bathroom.
November 29, 2024 at 11:51 AM