Correct. The student multiplied each digit of 43 by 6, and I think they were then minded to do the same for the addition. Not an error I’ve ever seen before.
So the student got 258, thought they were adding 4, got 702 and didn’t notice that it was much too large. I’ll be honest: I was stumped!
March 6, 2025 at 11:14 PM
Correct. The student multiplied each digit of 43 by 6, and I think they were then minded to do the same for the addition. Not an error I’ve ever seen before.
So the student got 258, thought they were adding 4, got 702 and didn’t notice that it was much too large. I’ll be honest: I was stumped!