Matt Cushman
@anthropicprincipal.bsky.social
Math and science enjoyer
This explains so much
November 4, 2025 at 1:56 PM
This explains so much
Gee why could this be, I have no idea
August 22, 2025 at 1:56 AM
Gee why could this be, I have no idea
Senate divided over whether to follow the Constitution
June 19, 2025 at 10:41 AM
Senate divided over whether to follow the Constitution
Project Golden Combover
May 22, 2025 at 4:19 PM
Project Golden Combover
The real war on Christmas
April 30, 2025 at 8:35 PM
The real war on Christmas
Who’s gonna tell her?
April 15, 2025 at 12:05 PM
Who’s gonna tell her?
So, what disk is on the y-axis, no matter how you turn this and orient the axes?
The one concentric with the big circle.
Easier than trying to compute these integrals!
The one concentric with the big circle.
Easier than trying to compute these integrals!
March 10, 2025 at 6:51 PM
So, what disk is on the y-axis, no matter how you turn this and orient the axes?
The one concentric with the big circle.
Easier than trying to compute these integrals!
The one concentric with the big circle.
Easier than trying to compute these integrals!
The likelihood of the chord being in a particular band of x values is proportional to the arc-length along the circle of that interval. That’s shorter near the middle, and longer towards the sides (one can write this down as an integral involving arcsin if you like)
March 10, 2025 at 6:51 PM
The likelihood of the chord being in a particular band of x values is proportional to the arc-length along the circle of that interval. That’s shorter near the middle, and longer towards the sides (one can write this down as an integral involving arcsin if you like)
Parameterize the vertical chords by where they hit the x axis. Note that (being a disk of radius 1), wherever it’s located in the circle, it will intersect some interval of chords of width 2.
March 10, 2025 at 6:51 PM
Parameterize the vertical chords by where they hit the x axis. Note that (being a disk of radius 1), wherever it’s located in the circle, it will intersect some interval of chords of width 2.
Choosing a random chord can be thought of as choosing a random slope, then a chord with that slope.
Fix any slope for the chord.
We will show that when the disk is in the center of the circle, it has the least prob of intersection.
Fix any slope for the chord.
We will show that when the disk is in the center of the circle, it has the least prob of intersection.
March 10, 2025 at 6:51 PM
Choosing a random chord can be thought of as choosing a random slope, then a chord with that slope.
Fix any slope for the chord.
We will show that when the disk is in the center of the circle, it has the least prob of intersection.
Fix any slope for the chord.
We will show that when the disk is in the center of the circle, it has the least prob of intersection.
Putnam problem A5: easy solution
March 10, 2025 at 6:51 PM
Putnam problem A5: easy solution
Now we’re whitewashing Watergate
November 9, 2024 at 9:16 AM
Now we’re whitewashing Watergate
C_4 isn’t exactly C_2 x C_2…
December 21, 2023 at 10:01 PM
C_4 isn’t exactly C_2 x C_2…
There are many things wrong with Chat-gpt’s response, but I think “2 is the simplest prime” is the winner
December 21, 2023 at 9:58 PM
There are many things wrong with Chat-gpt’s response, but I think “2 is the simplest prime” is the winner
