lexa!
@lexa.qexat.com
1.2K followers 360 following 6.7K posts
i love compilers and women hire me for OCaml dev!!
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lexa.qexat.com
literally reacted to the PR xD
Reposted by lexa!
david.sancho.dev
Day 2 of hacking before ICFP

Finally finished odoc markdown backend support in dune, it should make release nicer documentation sites (docusaurus, vitepress, etc) or even github itself

Before (odoc html) After (odoc to markdown |> vitepress)
lexa.qexat.com
yesss i saw this is very exciting!!!
Reposted by lexa!
dieworkwear.bsky.social
You gently run your hand through the rack. You can feel it—pure cotton, rich wool, Irish linen. The plump buttonholes are handsewn; the buttons attached with a firm shank. You flip the price tag over. It's affordable

You buy the jacket and go home, which is only 15 mins away. Your apt is $600/month
Headline reads: Altman says ChatGPT will soon allow erotic for adult users.
lexa.qexat.com
fuck these quizzes the old man goes before
lexa.qexat.com
not cut elimination sorry just cut
lexa.qexat.com
i mean the deduction theorem would arise from cut elimination anyway, that's not what i'm looking for :p

what interests me is transportation from theory to metatheory with a category theory perspective
lexa.qexat.com
i'm trying to express the informal idea that A → B ∈ Th ⊢ 𝓕(A) ⊢ 𝓕(B) ∈ M which can be read as "if A implies B in the theory, A entails B in the metatheory" (modus ponens again)
lexa.qexat.com
if Th satisfies (a → b) → Th a → Th b and M satisfies (M a → M b) → a → b then that is to say that Th admits modus ponens (a → b, a ⊢ b) as (M a → M b) → (Th a) → (Th b)

technically you could be satisfied with M (M a → M b) → M (Th a) → M (Th b) [Th wouldn't be free, bounded by M, harder to prove]
lexa.qexat.com
M is a functor, Th is a sort of "cofunctor", not as in contravariant [(a → b) → Th b → Th a] but as in the opposite direction [(Th a → Th b) → a → b]
lexa.qexat.com
it was yesterday night the stream lasted for almost 5 hours don't tell me you missed it
lexa.qexat.com
clearly you can tell i wrote this at almost 2 am because we're supposed to get (Th a → Th b) → M a → M b
lexa.qexat.com
the meme "it goes in the square hole" but with functors
lexa.qexat.com
← person who is trying way too hard to build a programming language on logical and categorical principles
lexa.qexat.com
if Th satisfies (a → b) → Th a → Th b and M satisfies (M a → M b) → a → b then that is to say that Th admits modus ponens (a → b, a ⊢ b) as (M a → M b) → (Th a) → (Th b)

technically you could be satisfied with M (M a → M b) → M (Th a) → M (Th b) [Th wouldn't be free, bounded by M, harder to prove]
Reposted by lexa!
isabelroses.com
the sanity of google software
Google wallet is not Google pay is not Google pay is not Google wallet is not Google check out is not Google wallet is not android pay is not Google pay send is not Google pay
lexa.qexat.com
what's funny is that graphic design is merely a side quest for me, and i wasnt very close them, just members of the same discord server that knew each other a bit more as regulars often do
lexa.qexat.com
i mentioned figma to someone half a decade ago and they reached me out last year to tell me that graphic design is their whole life now :')
Reposted by lexa!
Reposted by lexa!
hayleigh.dev
i've not even released clique yet and someone is already using it to build out their personal site!! the gleam community is just built different i swear
lexa.qexat.com
it's almost 1am excuse the word swapping
lexa.qexat.com
implicit modulars fix this
lexa.qexat.com
🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇🐇
lexa.qexat.com
happy birthday!!