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Reposted by lexa!

derek guy @dieworkwear.bsky.social · 13h

You gently run your hand through the rack. You can feel it—pure cotton, rich wool, Irish linen. The plump buttonholes are handsewn; the buttons attached with a firm shank. You flip the price tag over. It's affordable

You buy the jacket and go home, which is only 15 mins away. Your apt is $600/month

Headline reads: Altman says ChatGPT will soon allow erotic for adult users.

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lexa! @lexa.qexat.com · 11h

fuck these quizzes the old man goes before

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lexa! @lexa.qexat.com · 11h

not cut elimination sorry just cut

lexa! @lexa.qexat.com · 11h

i mean the deduction theorem would arise from cut elimination anyway, that's not what i'm looking for :p

what interests me is transportation from theory to metatheory with a category theory perspective

lexa! @lexa.qexat.com · 11h

wdym?

lexa! @lexa.qexat.com · 12h

i'm trying to express the informal idea that A → B ∈ Th ⊢ 𝓕(A) ⊢ 𝓕(B) ∈ M which can be read as "if A implies B in the theory, A entails B in the metatheory" (modus ponens again)

lexa! @lexa.qexat.com · 20h

if Th satisfies (a → b) → Th a → Th b and M satisfies (M a → M b) → a → b then that is to say that Th admits modus ponens (a → b, a ⊢ b) as (M a → M b) → (Th a) → (Th b)

technically you could be satisfied with M (M a → M b) → M (Th a) → M (Th b) [Th wouldn't be free, bounded by M, harder to prove]

lexa! @lexa.qexat.com · 12h

M is a functor, Th is a sort of "cofunctor", not as in contravariant [(a → b) → Th b → Th a] but as in the opposite direction [(Th a → Th b) → a → b]

lexa! @lexa.qexat.com · 13h

it was yesterday night the stream lasted for almost 5 hours don't tell me you missed it

lexa! @lexa.qexat.com · 13h

clearly you can tell i wrote this at almost 2 am because we're supposed to get (Th a → Th b) → M a → M b

lexa! @lexa.qexat.com · 20h

the meme "it goes in the square hole" but with functors

lexa! @lexa.qexat.com · 20h

← person who is trying way too hard to build a programming language on logical and categorical principles

lexa! @lexa.qexat.com · 20h

if Th satisfies (a → b) → Th a → Th b and M satisfies (M a → M b) → a → b then that is to say that Th admits modus ponens (a → b, a ⊢ b) as (M a → M b) → (Th a) → (Th b)

technically you could be satisfied with M (M a → M b) → M (Th a) → M (Th b) [Th wouldn't be free, bounded by M, harder to prove]

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Reposted by lexa!

isabel @isabelroses.com · 1d

the sanity of google software

Google wallet is not Google pay is not Google pay is not Google wallet is not Google check out is not Google wallet is not android pay is not Google pay send is not Google pay

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lexa! @lexa.qexat.com · 1d

what's funny is that graphic design is merely a side quest for me, and i wasnt very close them, just members of the same discord server that knew each other a bit more as regulars often do

lexa! @lexa.qexat.com · 1d

i mentioned figma to someone half a decade ago and they reached me out last year to tell me that graphic design is their whole life now :')

Reposted by lexa!

Adopt a Pet @adoptapet.bsky.social · 1d

Could this be your new buddy? Sienna, located in Chesterfield, MO.

Learn more: https://www.petfinder.com/rabbit/sienna-77335710/mo/chesterfield/missouri-house-rabbit-society-mo56/

Sienna is a Satin mix rabbit, available for adoption in Chesterfield, MO.

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Reposted by lexa!

hayleigh @hayleigh.dev · 26d

i've not even released clique yet and someone is already using it to build out their personal site!! the gleam community is just built different i swear

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lexa! @lexa.qexat.com · 1d

it's almost 1am excuse the word swapping

lexa! @lexa.qexat.com · 1d

what's up

lexa! @lexa.qexat.com · 1d

implicit modulars fix this