Andrew Stacey
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mathforge.org
Andrew Stacey
@mathforge.org
Mathematician: formerly academic (differential topology), currently educational (Head of Department in a UK secondary school).

Side interests in Maths & Programming & Art.

Website: https://loopspace.mathforge.org
3. Initial conditions. Two populations makes it obvious that you'll need two initial conditions.

Seemed to go okay. Managed to also bring in exponential of matrices which was fun!
November 12, 2025 at 8:11 PM
Just guessing here, but to render the eleven tiles would need a finer grid on the cube. I think I can see how to see each tile on a 3×3, but not smaller. So to render a spherical tiled knot on a n×n×n grid you'd need a 3n×3n×3n sized cube.
October 31, 2025 at 5:50 PM
Yeah, Adobe editions would be very useful.
October 26, 2025 at 8:34 PM
I read that as saying that I can't read books bought from bookshop.org on my kobo.

It'd be nice if I could as this sounds like a great way to support local bookshops with the convenience of ebooks.
Bookshop: Buy books online. Support local bookstores.
An online bookstore that financially supports local independent bookstores and gives back to the book community.
bookshop.org
October 26, 2025 at 6:03 PM
The bookshop.org FAQ says:

"Can I read my ebooks on my Kindle, Kobo, etc.?
• Ebooks from Bookshop.org must be read on either our Apple or Android app, or via a web browser, with the exception of DRM-free titles that can be downloaded and transferred to your reader app or device of choice."
Bookshop: Buy books online. Support local bookstores.
An online bookstore that financially supports local independent bookstores and gives back to the book community.
bookshop.org
October 26, 2025 at 6:03 PM
Exactly, so the binomial polynomials are the discrete analogues of the divided powers.
October 24, 2025 at 10:17 PM
I shall have to break my "no video" rule as this is one of those topics where I Have Opinions.
October 24, 2025 at 10:13 PM
Define the nth binomial polynomial as b_n(x) = n(n+1)(n+2)...(n+k-1)/k! then the summation operator on sequences takes b_n(x) to b_{n+1}(x).

Possibly easier to see in reverse: that the difference operator takes b_n to b_{n-1}
October 24, 2025 at 10:06 PM
Neither of which I want associated with the very deep and profound sense of wonder that I get when - after a lot of time and effort - I truly understand some piece of mathematics.
October 22, 2025 at 10:19 PM
Apologies for not being clear.

I'm objecting to the (over)use of the *word* beauty because (to me) it conveys a superficialness together with a sense of "if you don't see it yourself, you'll never be part of the in-crowd".
October 22, 2025 at 10:19 PM
I don't think that there's one replacement word, rather we use a more accurate word for each circumstance.

Incidentally, it's not a child-like appreciation of beauty that I'm objecting to, but a superficial one.
October 22, 2025 at 8:08 PM
I'd've bought one ... if I didn't already own a copy.

(Which, as it is half term, I am now reading)
October 22, 2025 at 6:51 PM
I just feel that the word "beauty" conveys something one either sees or doesn't and that if you've had to work at it - as in your beethoven example - then there'll be a more pertinent word that expresses what it is that you experience.
October 22, 2025 at 5:47 PM