Since m is <= n and q<n, it is indeed true that N is always equal to 10^x 2^y with x>=0 and y >0.
Since m is <= n and q<n, it is indeed true that N is always equal to 10^x 2^y with x>=0 and y >0.
So N = 5^m-n 2^m-q
So N = 5^m-n 2^m-q
Every integer ending in 5 is divisible by 5 such that: 1/N = (5^n*x)/(2^m*5^m) = (5^n-m * x) / (2^m) = x / (5^m-n * 2^m)
This means that: N = (5^m-n * 2^m) / x
Every integer ending in 5 is divisible by 5 such that: 1/N = (5^n*x)/(2^m*5^m) = (5^n-m * x) / (2^m) = x / (5^m-n * 2^m)
This means that: N = (5^m-n * 2^m) / x