Karen Campe
@karencampe.bsky.social
1.7K followers 460 following 1.7K posts
Math teacher using technology for understanding Reflections & Tangents Blog: karendcampe.wordpress.com
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Reposted by Karen Campe
"One of the best things you can do as a teacher is to be in the situation of a student, so you know what it feels like again"
At #nctmatl25 #mtbos #mathed
Happy Thursday Mike! (My favorite of the puzzle days 😉)
❤️❤️❤️ wonderful!
{reminder to drink your water}
Have a great conference! Keep posting for those of us playing along from home...
Hello #iTeachMath #MathsToday folks... these Yohaku puzzles from Mike are an excellent thinking task for students at many levels. Enjoy!
Start your day with this #yohaku. Fill in cells with 9 different factors of 384 to get totals shown in each row/column. #mathsky #iTeachMath
Use 9 different factors of 384  in a 3 by 3 grid. The numbers in the top row add to 34. The numbers in the middle row add to 121. The numbers in the bottom row add to 13. The numbers in the left column add to 32. The numbers in the middle column add to 120. The numbers in the right column add to 16.
This is a lovely puzzle to find a second "solution" by letting some factors repeat.
What lovely powers today! Can you see where the odd factors of 384 have to go?
Reposted by Karen Campe
"When we are so solution focused, students are afraid to be wrong... And I wonder how that applies to voters. How can we ever feel safe to change our minds?"

When @cluzniak.bsky.social speaks, I am seated and listening and learning. #NCSMRiseUp #NCSM2025
Ok if there are 15 students, for each of them to have a diff nonzero number of candles, you'd need 120 candles (sum of 1,2,3,...15 = 120)
If 16 students, you'd need 136.
Therefore you don't have enough candles for each student to have a unique number. QED.
A week of school (5 days) or a calendar week? Did you have 85 candles or 119 to distribute?
6 miles/5 minutes multiply by 6/6 -->
36 miles/30 minutes

7 miles/6 minutes mult by 5/5 -->
35 miles/30 minutes

So 6 mi/5 min is faster!

#MathStratChat
#MentalMathMonday
#iTeachMath
Students will do either, whichever they find more accessible. Some don't remember exterior angle theorem, but triangle sum and linear pairs still works!
(More than one path to solve many angle-chase problems 😊
Have a great time, will look forward to seeing what you share here.
Wish I could be there, sadly not coming to conference. Be sure to post for those of us playing along from home!

{are you coming to ATMNE October 30-31?}
I used 3 ideas:
-Right triangle with hypotenuse = 10
-Geometric mean** of the 2 parts of diameter
-the question asks for area, not the dimensions separately

**thanks to @howiehua.bsky.social I've had the different means on my mind.
In marked diagram --> y is geometric mean of w and x.
Semicircle and rectangle, with base of rectangle along diameter of semicircle, and top edge of rectangle tangent to semicircle. 

Left side of rectangle divides diameter of semicircle into two parts, labeled w and x. 
Let y be the part of the left side of rectangle from bottom corner up to semicircle intersection. 

Then y is geometric mean of w and x: 
w/y = y/x
Cool!!
My usual approach (w/out technology) is rational root theorem and use the remainder theorem to help P(root) = 0 so can do some easy tests with 1, -1, 2 etc.
Yes, that's typical phrasing in US.
The marked angle is half the sum of the intercepted arcs, so (1/2)•(50+110) --> (1/2)•160 = 80°

This is one of 7 angle-arc cases that can be boiled down to "one big rule"

#iTeachMath #MathsToday #UKMathsChat
Big Rule: Identify the location of the angle’s vertex, which gives the relationship of the angle measure to the intercepted arc(s):

At center: angle = arc
On circle: angle = (1/2)•arc
Inside circle: angle = (1/2)•(arc 1 + arc 2)
Outside circle: angle = (1/2)•(arc 1 – arc 2)

Notes: This condenses 7 rules into 4 rules. Use these varied situations to practice circle vocabulary. In class, I would pantomime an “intercepted arc” with my two arms, as if I were a football player making an interception.
Nicely done, David.
At first glance, cubic not easily factored.
Did you use rational root theorem or a graphing calculator to help finding that factorization... or other ideas??
Would love to hear more about your thinking.
#iTeachMath #ProblemSolving